00:01
Hi, in the first subpart of the question, we need to find the resistance of the 100 watts bulb.
00:10
So the power in this case is 100 watts which is connected to a potential difference of 120 volts.
00:19
So we know the relationship between power, voltage and resistance as p is equal to v square by r we need to find the resistance so upon rearranging the equation we'll get r is equal to v square by p now we know the values of v and p so we just need to substitute the values and solve for it that will be 120 square divided by p is 100 this will give us the final answer for the resistance of the 100 bulb as 144 homes.
00:57
So we have sold the first subpart of this question.
01:04
In the second subpart of the question we need to find the resistance of the 60 watts bulb.
01:10
So power in this case is 60 watts which is connected to the same potential difference of 120 volts.
01:17
So we can use the same equation of resistance as we used in the first subpart which is r.
01:24
R is equal to v square by p.
01:30
Now upon substituting the values, p is 120, so 120 squared divided by 60.
01:41
The fine answer for the resistance of the 60 watt bulb would be 240 oms.
01:51
Now we have our answer for the second support also.
01:56
Now in the third support of the question we need to find the current drawn by the 100 watt bulb as well as the 60 watt bulbs...