Required information NOTE: This is a multi-part question....

Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. The press shown is used to emboss a small seal at E. 200 mm 400 mm C B 15° P 20° 60° A D E Knowing that P = 350 N, determine the vertical component of the force exerted on the seal. The vertical component of the force is E = ____ N.

Transcript

00:01 We're asked to find the vertical component of the force that's exerted at this point d, seal, and we're also asked to find the reaction at point a due to the input force of 250 nons at this point c.

00:16 So to start with, to solve this problem, we can use the expression that the sum of all moments at a point a is equal to zero.

00:31 And we can write this as the vertical component of the force at d times the length ad is equal to the force p times the length ah.

00:52 So we'll start part a by finding some unknown lengths in this free body diagram so we can plug into this equation and solve for the vertical component of the force.

01:09 So to start with, we'll find the length from b to g, and that's going to be equal to 200 times the sign of 60 degrees, and that will give us a length of 173 .2 millimeters.

01:34 And next we'll find the length from a to g.

01:39 So the length from a to g, that's going to be equal to 200 times the cosine of 60, and that will give us a length of 100 millimeters.

01:58 And next we're going to find the length from g with d.

02:05 And that's going to be equal to the length bg divided by the tangent of 70 degrees.

02:19 And that's going to be equal 63 .04 millimeters.

02:32 So now you can say that the length ad is equal to ag plus gd.

02:44 And that's going to be equal to 163 .04 millimeters and we can say that a h is equal to ag plus bc times the cosine of 15 degrees and that's going to give us the length of 484 .24 .4 millioners so we now have everything to plug into this equation we can now use this equation here and we can solve for the unknown d of y.

03:44 So we plug in, so we have the unknown d of y times 163 .04 is equal to 250 times 486 .4.

04:12 And solving this for d of y will give us a force of 745 .829 newtons in the upwards direction.

04:35 And we're now going to solve part b where it asks us to find the reaction at the point a.

04:47 So for part b, we can assume now that this point d will be at equilibrium whenever it's at its highest point.

04:56 So for part b, we're going to say that, we're going to say that the sum of moments about the point d is equal to zero at equilibrium...

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