Question

"The pressure of water inside a closed pipe is 3 x 10^5 N/m². This pressure reduces to 2 x 10^5 N/mon opening the valve of the pipe. Calculate the speed of water flowing through the pipe. [Density of water = 1000 kg/m]"

Name: the pressure of water inside a closed pipe is 3 x 105 nm2 this pressure reduces to 2 x 105 nmon opening the valve of the pipe calculate the speed of water flowing through the pipe density of water 100
Uploaded: 2022-05-01T09:20:17-08:00
Duration: 2 min 25 s
Channel: Dharmendra Maheshwari
Description: the pressure of water inside a closed pipe is 3 x 105 nm2 this pressure reduces to 2 x 105 nmon opening the valve of the pipe calculate the speed of water flowing through the pipe density of water 100

          "The pressure of water inside a closed pipe is 3 x 10^5 N/m². This pressure reduces to 2 x 10^5 N/mon opening the valve of the pipe. Calculate the speed of 
water flowing through the pipe. [Density of water = 1000 kg/m]"

Added by Mia M.

Practice Problem in Physics for the JEE Main and Advanced

Abhay Kumar 2015 Edition

Chapter 9

Instant Answer

Solved by Expert Dharmendra Maheshwari

05/01/2022

Step 1

Step 1: Given data The pressure inside the closed pipe, P1 = 3 x 10^5 N/m² The pressure when the valve is opened, P2 = 2 x 10^5 N/m² Density of water, ρ = 1000 kg/m³ Show more…

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"The pressure of water inside a closed pipe is 3 x 10^5 N/m². This pressure reduces to 2 x 10^5 N/mon opening the valve of the pipe. Calculate the speed of water flowing through the pipe. [Density of water = 1000 kg/m]"