00:02
Atomic emission spectra arise from electron transitions from higher to lower energy orbitals.
00:10
The blue line at 434 .7 nanometers in for mercury is a 7d to 6p electron drop transition.
00:36
For part a, we are asked to give the nl.
00:45
And m possible quantum numbers for the 7d orbital.
00:51
Remember n is the principal quantum number and that is given as 7.
01:00
And just a second here.
01:28
I've forgotten which principle this is.
01:30
I feel like it's this one but i'm going to have to look it up.
01:33
Hang on just a second here.
01:35
Having a bad memory glitch.
01:45
I'm looking up to see how to spell principal quantum number.
01:50
Now it's al and it can be one through seven.
02:04
And we have given seven.
02:08
L represents which sub level we're in.
02:12
It's called angular momentum, and it basically tells us our shape.
02:23
And it's 0 for an s, 1 for a p, 2 for a d, and 3 for an f.
02:36
And we see that this is a d sub level, so we're going to have an l of 2.
02:43
Our magnetic quantum number, m, gives us spatial orientation.
03:00
There are five orbitals in the d sub level, and we call these 0 plus 1, minus 1.
03:17
So minus is on the wrong side there.
03:22
And plus 2 and minus 2.
03:26
So those are my possible m's.
03:29
So here's my possible n, my l, and my m.
03:36
Our next question says, give the same information for the 6p sub -level.
03:45
And this, n will be 6.
03:49
L, since this is p, will be 1.
03:51
And m, since there are three orbitals, can be negative 1, 0, or plus 1...