00:01
Hi, i'm david and i'm here to help you answer your question.
00:03
Now let me pick up your question here.
00:06
In the question here, let me summarize the question by the tree diagram.
00:10
Here we have the three events a1, a2 and a3.
00:14
So i will have 1, 2 and 3.
00:18
This will be the a1, a2 and the a3.
00:24
The probability a1 equal to the zbon 2, a2 equal to zupon 5 -0.
00:30
And the a3 equal to the zupon 3 0.
00:34
Now we will have the probability even be given the a1 -83.
00:39
So there will be, we have the b and this one will be not b.
00:44
This will be the b and this will be the not b.
00:48
There could be the b and this could be the not b.
00:53
So probability will be given that it will come from the a1 equal to the zubon form.
01:01
So this is going to be the 014.
01:03
Then the common one will be 1 minus 014 equal to the 016.
01:07
Then probability be given that it comes from the a2 equal to the 0 .5.
01:13
The common law also 0155.
01:15
The last one will be the 012...