The probabilities that a batch of 4 computers will contain 0, 1, 2, 3, and 4 defective computers are 0.4979, 0.3793, 0.1084, 0.0138, and 0.0007, respectively. Find the standard deviation for the probability distribution. How to solve using a TI-83?
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Step 1
To do this, we multiply the number of defective computers by their respective probabilities and sum them up: Mean (μ) = $0 \cdot 0.4979 + 1 \cdot 0.3793 + 2 \cdot 0.1084 + 3 \cdot 0.0138 + 4 \cdot 0.0007$ Mean (μ) = $0 + 0.3793 + 0.2168 + 0.0414 + 0.0028$ Mean Show more…
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