00:01
In the first part, we have total probability is equal to summation i, p i is equal to 1.
00:17
Further, we have p 0 plus p 1 plus p 2 is equal to 1.
00:28
Then we have 3cq plus 4c minus 10c square plus 5c minus 1 is equal to 1.
00:42
Because we have put the values of p 0, p 1 and p 2 here.
00:48
Then in the next step, we have 3cq minus 10c square plus 9c will be equal to 2.
00:59
And then we have 3cq minus 10c square plus 9c minus 2 is equal to 0.
01:09
Now solving for c, we get c is equal to 2 or c is equal to 1 or c is equal to 1 divided by 3.
01:32
But c is equal to 2 and c is equal to 1 are not valid because that will give p 0 is equal to 3cq greater than 1 which is not possible.
02:13
So c will be equal to 1 divided by 3.
02:19
Now in the next part which is part b, we have p 1 less than x less than equal to 2 is equal to p x is equal to 2 is equal to p 2 is equal to 5c minus 1...