00:01
Hi, i'm david and i'm here to have you answer your question.
00:04
Now let me bring up your question here.
00:07
In this question, the probability of the successful rocket launch is equal to 0 .16.
00:12
So we are given that the probability of the success equal to the 06.
00:17
Suppose that the launch attempts are much until their three successful consecutive launches occurs.
00:26
What is the probability that we want to find the probability that the probability that the 6th? attempt needed.
00:36
So in that you get the six attempts like this, we will have the outcomes for the six attempts here.
00:44
One, two, three, four, five, and the six.
00:49
In order to have exactly the six attempts needed, the last three of them must be successful.
00:57
And now on this position here, it must be failure.
01:00
Otherwise, it will stop under fifth.
01:02
So therefore, this one should should be the failure.
01:06
Now the order of them, it can be either the success or the failure.
01:14
So if we will split this one into the two cases that it will be the one success and one failure and then two success and then.
01:24
So let's try to end up the probability for those of them first.
01:30
This one, the founder, it will equal to the we can do it here.
01:35
Now, to get the failure in the third one, we'll have the 0 .4, and then the success on this one will be 0 .6.
01:47
This one will be 0 .6 .6.
01:50
Now, this will be the probability, the first and second one, it can be either four cases here.
01:59
It can be either the success, success, success failure, and failure success on the failure and failure.
02:05
So for the success, success, it equals 0 .6 power 2.
02:10
For the success and failure, equal to 0 .6 times with the 0 .4...