00:01
Hello student, the probability of being alone to log on computer system from remote during busy period is equal to 0 .7.
00:11
Now suppose a 10 independent events are made.
00:15
Now suppose a y represents the number of attempt up to including first successful attempt then distribution function for geometric distribution.
00:27
So here 1 minus p rest to y minus 1 into p.
00:34
So here we have given probability is equal to 0 .7.
00:39
So here 1 minus 0 .7 rest to y minus 1 into 0 .7.
00:46
Now in the next bit here we have to find out the probability of y is equal to 4.
00:53
So here 1 minus 0 .7 rest to 4 minus 1 into 0 .7.
01:03
So solving it will give us the probability of y is equal to 4 which is equal to 0 .0189.
01:13
Now in the next bit here we have to find out the probability of y greater than or equal to 5.
01:24
So here probability of y greater than or equal to 5 is equal to 1 minus g of 1 plus g of 2 plus g of 3 plus g of so using a calculator 1 minus 0 .70 plus 0 .21 plus 0 .06 plus 0 .01...