Question

E 25° T C400 mm D mm 1140 Z B A X The door is supported by the hinges along line BC. A force of T = 480 N is applied to the door at point A and acts along line AE. Point E lies along the midpoint of the horizontal upper edge of the support structure.

          E
25°
T
C400
mm D
mm
1140
Z
B
A
X
The door is supported by the hinges along line BC. A force of T = 480 N is applied to the door at point A and acts
along line AE. Point E lies along the midpoint of the horizontal upper edge of the support structure.

E
25°
T
C400
mm D
mm
1140
Z
B
A
X
The door is supported by the hinges along line BC. A force of T = 480 N is applied to the door at point A and acts
along line AE. Point E lies along the midpoint of the horizontal upper edge of the support structure.

Added by Angela J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Gopal Sharma

Step 1

First, we need to find the moment arm, which is the perpendicular distance between line BC and line AE. Since point E lies along the midpoint of the horizontal upper edge of the support structure, the moment arm is the distance from point E to line BC. Show more…

Show all steps

Thanks for your feedback!

The question states: Calculate the moment of force T about line BC in the direction from B to C. (include units with answer) I got my unit vector of BC cross product with T as [147.116i -113.94j + 244.349k], so shouldn't a dot product with the unit vector BC provide the right answer? Not sure where I am going wrong here. The answer should be in N-m. Thanks. c400 mm E The door is supported by the hinges along line BC. A force of T = 480 N is applied to the door at point A and acts along line AE. Point E lies along the midpoint of the horizontal upper edge of the support structure.