View Policies Current Attempt in Progress The radius of Earth is 6370 km, and its orbital speed about the Sun is 30 km/s. Suppose Earth moves past an observer at this speed. To the observer, by how much does Earth's diameter contract along the direction of motion?
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00 \times 10^5 \, \text{km/s} \) is the speed of light. Show more…
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The radius of Earth is 6370 km, and its orbital speed about the Sun is 30 km/s. Suppose Earth moves past an observer at this speed. To the observer, by how much does Earth’s diameter contract along the direction of motion?
Adi S.
The radius of Earth is $6370 \mathrm{~km}$, and its orbital speed about the Sun is $30 \mathrm{~km} / \mathrm{s}$. Suppose Earth moves past an observer at this speed. To the observer, by how much does Earth's diameter contract along the direction of motion?
The radius of Earth is $6370 \mathrm{km},$ and its orbital speed about the Sun is 30 $\mathrm{km} / \mathrm{s}$ . Suppose Earth moves past an observer at this speed. To the observer, by how much does Earth's diameter contract alono the direction of motion?
Ma Ednelyn L.
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