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Hello students.
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Today we will discuss about this question.
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In this question we are given that the random variable w takes the value that is 1 .5, 3, 6 and 7 with probabilities that is 0 .2, 0 .25, 0 .4 and 0 .15 respectively.
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Then here we need to compute the expectations of w.
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E of w is equal to question my.
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Then we need to compute expectations of w square is equal to question mark and then we need to find the variance of w that is equals to question mark.
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So here first of all we can write here it is w and p of w here 1 .5367.
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So p of w will be 0 .2, 0 .25, 0 .4 ,0 .15.
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Now, e of w, that can be given as summation of w of p of w.
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So that is equals to 15 multiplied by 1 .5 multiplied by 0 .2 plus 3 multiplied by 0 .25 plus 6 multiplied by 0 .4 plus 7 multiplied by 0 .15.
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So that is equals to we will get 4 .5.
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So that will be the required expected value of w...