Question

The range of the value of coefficient of determination is between: \[ \begin{array}{c} \cdot \leq r^{\top} \leq 10 \\ -1 \leq r^{\top} \leq 1 \quad 0 \\ -1 \leq r^{\top} \leq \cdot 0 \\ \cdot \leq r^{\top} \leq \infty \end{array} \] ????? 6 If the variance is 8 and sample size 10 , then the standard deviation is \[ \begin{array}{c} 2.830 \\ 80 \\ 640 \end{array} \]

          The range of the value of coefficient of determination is between:
\[
\begin{array}{c}
\cdot \leq r^{\top} \leq 10 \\
-1 \leq r^{\top} \leq 1 \quad 0 \\
-1 \leq r^{\top} \leq \cdot 0 \\
\cdot \leq r^{\top} \leq \infty
\end{array}
\]
????? 6
If the variance is 8 and sample size 10 , then the standard deviation is
\[
\begin{array}{c}
2.830 \\
80 \\
640
\end{array}
\]

The range of the value of coefficient of determination is between:

·≤ r^⊤≤ 10

-1 ≤ r^⊤≤ 1 0

-1 ≤ r^⊤≤· 0
·≤ r^⊤≤∞

????? 6
If the variance is 8 and sample size 10 , then the standard deviation is

2.830

80

640

Added by Ernest C.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Jainendra Kumar

Step 1

- It is the square of the correlation coefficient \( r \), which ranges between -1 and 1. Therefore, \( r^2 \) must range from \( 0 \) to \( 1 \) because squaring any real number between -1 and 1 will result in a value between 0 and 1. Show more…

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The range of the value of coefficient of determination is between: \[ \begin{array}{c} \cdot \leq r^{\top} \leq 10 \\ -1 \leq r^{\top} \leq 1 \quad 0 \\ -1 \leq r^{\top} \leq \cdot 0 \\ \cdot \leq r^{\top} \leq \infty \end{array} \] إسوال 6 If the variance is 8 and sample size 10 , then the standard deviation is \[ \begin{array}{c} 2.830 \\ 80 \\ 640 \end{array} \]