00:02
Hi students, in this question we will be using the arrhenius equation to solve.
00:07
We will be using the arrhenius equation to find the activation energy.
00:15
And the arhanius equation states that k is equal to a, e, raised to the power minus e .a divided by rt.
00:26
Now we will write our equation 1 at k1 comma k2 and the temperature here will be t1 comma t2.
00:40
So the equation becomes ln k2 divided by k1 equals to ea that is activation energy divided by r, this whole will be in bracket 1 divided by t1 minus 1 divided by t 2.
01:02
So this is our equation 1.
01:05
On solving this we get ea is equal to r divided by 1 divided by t minus 1 divided by t2.
01:18
Ln k2 divided by k1.
01:24
So this will be the required equation for for finding the activation energy.
01:31
The initial temperature, that is t1, is equal to 718 kelvin, and the rate constant k1 is equal to 1 .1 multiplied by 10 -rays to the power minus 2, mole inverse, liter, second inverse...