The rate constant is 4.23 x 10^-2 M^-1s^-1 at 35 degrees Celsius. The activation energy of this reaction is 9.42 kJ/mol. What would the rate constant be at 50 degrees Celsius?
Added by Lourdes B.
Step 1
23 x 10^-2 M^-1s^-1 Ea = activation energy = 9.42 kJ/mol = 9420 J/mol R = gas constant = 8.314 J/mol*K T1 = temperature in Kelvin at 35 degrees Celsius = 35 + 273 = 308 K T2 = temperature in Kelvin at 50 degrees Celsius = 50 + 273 = 323 K Show more…
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