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The rate of a certain reaction is given by the following rate law: rate =k[NO]^(2)[O_(2)] Use this information to answer the question below. At a certain concentration of NO and O_(2), the initial rate of reaction is 0.180(M)/(s). What would the initial rate of the reaction be if the concentration of NO were doubled? Be sure your answer has the correct number of significant digits. The rate of a certain reaction is given by the following rate law: rate=k[NO]2[0] Use this information to answer the question below. At a certain concentration of NO and O2the initial rate of reaction is 0.180Ms.What would the initial rate of the reaction be if the concentration of NO were doubled? Be sure your answer has the correct number of significant digits. M

          The rate of a certain reaction is given by the following rate law:
 rate =k[NO]^(2)[O_(2)]
Use this information to answer the question below.
At a certain concentration of NO and O_(2), the initial rate of reaction is 0.180(M)/(s). What would the initial rate of the reaction be if the concentration of NO were doubled? Be sure your answer has the correct number of significant digits.
The rate of a certain reaction is given by the following rate law:
rate=k[NO]2[0] Use this information to answer the question below.
At a certain concentration of NO and O2the initial rate of reaction is 0.180Ms.What would the initial rate of the reaction be if the concentration of NO were doubled? Be sure your answer has the correct number of significant digits.
M

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the rate of a certain reaction is given by the following rate law rate kno2o2 use this information to answer the question below at a certain concentration of no and o2 the initial rate of 12827

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Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Susan Hallstrom

02/19/2024

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Step 1: Given rate law is rate = k[NO]^2[O2] Show more…

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The rate of a certain reaction is given by the following rate law: rate =k[NO]^(2)[O_(2)] Use this information to answer the question below. At a certain concentration of NO and O_(2), the initial rate of reaction is 0.180(M)/(s). What would the initial rate of the reaction be if the concentration of NO were doubled? Be sure your answer has the correct number of significant digits. The rate of a certain reaction is given by the following rate law: rate=k[NO]2[0] Use this information to answer the question below. At a certain concentration of NO and O2the initial rate of reaction is 0.180Ms.What would the initial rate of the reaction be if the concentration of NO were doubled? Be sure your answer has the correct number of significant digits. M

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Transcript

00:01 To answer several questions.

00:02 Question number one.

00:04 Reaction order in h2.

00:15 And i don't know why i wrote it like this.

00:17 This is totally wrong.

00:21 Because i just finished a different kind of problem.

00:26 There we go.

00:27 And that will be first order.

00:35 And then our second question is reaction order in i2.

00:49 That is also first order.

00:56 Next, we'll have overall.

01:01 Reaction order.

01:03 That will be second order.

01:13 Okay, now my next question is a little longer.

01:19 The initial rate is given as 0 .040 molarity per second.

01:41 If the concentration of h2 is doubled, what is the new initial rate? so what we'll do on this one is we'll take this value times two because if we double the concentration of a first order reactant we double the rate.

02:18 Next what should i use? how about this one? we measure the rate to be 3 .0 times 10 to the fourth meters per second and we measure our h2 concentration to be 1 .2 molar, and we measure our i2 concentration to be 0 .62 molar, we're going to find k.

03:02 K will equal our rate divided by our h2 concentration times our i2 concentration...

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