00:01
Hello students, here in this question a rate of reaction with the concentration of n2 along with its rate law is given.
00:07
Here we have and says that here in this question overall order of the reaction is 2 plus 2 that is the power of the reactant coefficient that will be 4 over here that we already given.
00:18
We have to find out what will be the rate if the concentration of the n2 is half.
00:22
So here we have to write the rate that it will be equal to rate constant into concentration of n2 square into concentration of the h2 square.
00:30
So here we can say that the reaction is second order with respect to the nitrogen.
00:35
So it's clearly depending upon the rate.
00:38
So the rate is directly proportional to the concentration of n2 over here.
00:43
So if the concentration of the n2 is getting halved over here what will happens to the rate? here rate become one fourth.
00:59
So as a result the rate over here will become 7 into 10 raised to 3 molar per second divided by 4.
01:07
So as a result of that here we will get the rate of the reaction after the concentration of the n2 is halved as 1750 molar per second...