The RC circuit shown in the figure has resistance of R=5,8k\Omega and the capacitance of
C=4,7\mu F. The capacitor is initially charged at a voltage V_(0)=31,6V at t=0,when the
switch is closed. How long does it take for the current running in the circuit to go down to 53%
of its initial value? Express your answer in units of ms (milliseconds) using two decimal places.
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