Question

5. The reaction between ethyl iodide and hydroxide ion in ethanol (C$_2$H$_5$OH) solution: C$_2$H$_5$I + OH$^-$ $ ightarrow$ C$_2$H$_5$OH + I$^-$ has an activation energy of 86.8 kJ/mol and a frequency factor of 2.10 × 10$^{11}$ M$^{-1}$s$^{-1}$. a) Predict the rate constant for the reaction at 35 $^circ$C. b) A solution of KOH in ethanol is made up by dissolving 0.335 g KOH in ethanol to form 250.0 ml of solution. Similarly, 1.453 g of C$_2$H$_5$I is dissolved in ethanol to form 250.0 ml of solution. Equal volumes of the two solutions are mixed. Assuming the reaction is first order in each reactant, solve the initial rate at 35 $^circ$C. c) Which reagent is limiting, assuming the reaction proceeds to completion?

          5.
The reaction between ethyl iodide and hydroxide ion in ethanol (C$_2$H$_5$OH) solution:
C$_2$H$_5$I + OH$^-$ $
ightarrow$ C$_2$H$_5$OH + I$^-$ 
has an activation energy of 86.8 kJ/mol and a frequency factor of 2.10 × 10$^{11}$ M$^{-1}$s$^{-1}$.
a) Predict the rate constant for the reaction at 35 $^circ$C.
b) A solution of KOH in ethanol is made up by dissolving 0.335 g KOH in ethanol to form
250.0 ml of solution. Similarly, 1.453 g of C$_2$H$_5$I is dissolved in ethanol to form
250.0 ml of solution. Equal volumes of the two solutions are mixed. Assuming the reaction
is first order in each reactant, solve the initial rate at 35 $^circ$C.
c) Which reagent is limiting, assuming the reaction proceeds to completion?

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5.
The reaction between ethyl iodide and hydroxide ion in ethanol (C2H5OH) solution:
C2H5I + OH^- ightarrow C2H5OH + I^-
has an activation energy of 86.8 kJ/mol and a frequency factor of 2.10 × 10^11 M^-1s^-1.
a) Predict the rate constant for the reaction at 35 ^circC.
b) A solution of KOH in ethanol is made up by dissolving 0.335 g KOH in ethanol to form
250.0 ml of solution. Similarly, 1.453 g of C2H5I is dissolved in ethanol to form
250.0 ml of solution. Equal volumes of the two solutions are mixed. Assuming the reaction
is first order in each reactant, solve the initial rate at 35 ^circC.
c) Which reagent is limiting, assuming the reaction proceeds to completion?

Added by Michael M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

07/15/2022

Step 1

10 x \( 10^{10} \) M\(^{-1}\)s\(^{-1}\)), - \( E_a \) is the activation energy (86.8 kJ/mol), - \( R \) is the gas constant (8.314 J/mol·K), and - \( T \) is the temperature in Kelvin (35 °C + 273.15 = 308.15 K). Show more…

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Transcript

00:01 The reaction given in the question is c2h5i plus oh minus gives as to c2h5 ohh plus i minus.

00:10 For this in part a, we have to get the rate constant for this reaction.

00:17 To get rate constant, the formula is k is equal to archenius constant into e par minus ea, that is, activation energy divided by rt.

00:26 Now, if we substitute the values, we'll be getting 2 .1 multiplied by 10 power 11 into e power.

00:36 The value of activation energy is given 86 .8 kilo juice.

00:42 86 .8 kilo, that is 10 power 3 divided by r is 8 .3, multiplied by temperature.

00:54 Temperature.

00:54 Temperature is given 35 degrees celsius.

00:59 Now this can be converted into kelvin's it will be 308 kelvin that is basically adding 273 to this so multiplied by 308.

01:08 Upon solving this we'll be getting 2 .1 into 10 power 11 multiplied by 1 .9 into 10 power minus 15 equals 3 .99 into 10 power minus 4 second inverse.

01:24 This is the value of rate constant.

01:29 Now, if we go to part b of this question, we see the mass of k -earch is given us 0 .335 grams.

01:40 And molar mass of it, we know, is 56 .0 grams per mole.

01:48 If we find the number of moles, it will be 0 .335 divided by 56.

01:53 It is 0 .00598.

02:00 Similarly for c2 h5i we find the number of moles is equal to the mass is 1 .453 grams divided by the molar mass of this is 155 which will give 0 .00937.

02:18 We have moles...

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