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Dear students, question is, the reaction n2 plus o2 gives rise to 2 no is carried out at a temperature at which kc value is 0 .055.
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The reaction mixture starts with only the product no, concentration is 0 .03 molar and no reactants.
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We have to calculate the equilibrium concentration of nitrogen, oxygen and nitric oxide.
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Now let us write the equation once again, n2 plus o2.
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Gives rise to 2 no.
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So initial concentration of no is 0 .03 molar, these are 0.
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For example, at equilibrium, 0 .03 x moles of no has broken into nitrogen and oxygen.
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Now since 2 moles gives 1 mole of nitrogen and 1 mole of oxygen, so x -mole will give xx2 mole of nitrogen and x by 2 mole of oxygen.
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Now, we know kc equal to molar concentration of for this equation no is the product.
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So we will write in the product form, no squared by n2, divided by n2, implies kc is 0 .055, which is equal to 0 .03 minus x whole square divided by x by 2 multiplied by 2 multiplied by x by 2 implies 0 .055 equal to 0 .03 minus x multiplied by 2 by x, you can write as whole square...