00:01
This question let's start with our combustion reaction.
00:04
C5h12 reacts with oxygen and a combustion reaction of products are co2 and h2.
00:10
And h2o to balance this, we'll need a 5 here, a 6 here, that's 10, 16, and 8 here.
00:17
We have 5 .0 grams of pentane and that react with 5 .0 grams of oxygen gas and produce 20 .4 grams of carbon.
00:32
Carbon dioxide, what is the percent yield? so let's calculate both reactants to co2 to find the theoretical yield.
00:40
Starting from 5 .0 grams of c5h12.
00:44
Over to moles here.
00:47
This is 72 .0 grams of c5h12 in one mole, one mole of c5h12 to five moles of co2 and one mole of c5h2 and one mole of c5 co2 is a mass of 44 .0 grams of co2.
01:09
This gives me 5 .0 divided by 72 .0 times 5 times 44.
01:16
And to 2 sig figs, i get 15 grams of co2 produced.
01:21
And then based on the second reactant, we have 5 .0 grams of oxygen.
01:26
Molar mass here is 32 .0 grams of 02 in 1 mole of 02...