00:01
Okay, so we have a chemical reaction and we're told that we want to produce 9 .81 liters of chlorine, cl2, at stp.
00:13
And if we want to do that, how much, how many grams of potassium per manganate would be needed? now, stp is very important here because we have a shortcut.
00:23
At stp, one mole of any gas has a volume of 22 .4 liters.
00:31
So we can use that to help us convert liters into moles.
00:36
And so we have 9 .81 liters of chlorine gas.
00:42
We can use that fact that one mole with any gas, so here, chlorine gas, has a volume of 22 .4 liters at stp.
00:52
You can see liters canc out.
00:58
Now that we're in moles, we have to convert between chlorine and potassium permanganate.
01:03
To do that, we need the coefficients from the balanced chemical equation.
01:08
For every two moles of potassium per manganate, we use two coming from the balanced chemical equation.
01:19
We're going to make five moles of cl2, again from the balanced chemical equation...