Question

The resulting pH of a solution when 100 mL of 0.860 M NH3 is mixed with 100 mL of 0.468 M HBr is ___. For NH3, Kb = 1.8 × 10^(-5).

Name: the resulting ph of a solution when 100 ml of 0860 m nh3 is mixed with 100 ml of 0468 m hbr is for nh3 kb 18 105 70377
Uploaded: 2023-08-07T22:04:31-08:00
Duration: 2 min 20 s
Channel: David Collins
Description: the resulting ph of a solution when 100 ml of 0860 m nh3 is mixed with 100 ml of 0468 m hbr is for nh3 kb 18 105 70377

          The resulting pH of a solution when 100 mL of 0.860 M NH3 is mixed with 100 mL of 0.468 M HBr is ___.
For NH3, Kb = 1.8 × 10^(-5).

Added by Juan Carlos D.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

08/07/2023

Step 1

First, we need to find the initial moles of NH3 and HBr. moles of NH3 = 0.860 M * 0.100 L = 0.0860 moles moles of HBr = 0.468 M * 0.100 L = 0.0468 moles Show more…

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