Question

The rod is not to slip downward, however large the force P may be, i.e., the arrangement is said to be self-locking. Neglecting the weight of the cylinder, the minimum coefficients of static friction at A may have any value, but at B and Cthey have to be not less than tan(θ/2).

Name: the rod is not to slip downward however large the force p may be ie the arrangement is said to be self locking neglecting the weight of the cylinder the minimum coefficients of static fricti 22303
Uploaded: 2022-12-11T20:02:44-08:00
Duration: 1 min 40 s
Channel: Penny Riley
Description: the rod is not to slip downward however large the force p may be ie the arrangement is said to be self locking neglecting the weight of the cylinder the minimum coefficients of static fricti 22303

          The rod is not to slip downward, however large the force P may be, i.e., the arrangement is said to be self-locking. Neglecting the weight of the cylinder, the minimum coefficients of static friction at A may have any value, but at B and Cthey have to be not less than tan(θ/2).

Added by David G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Penny Riley

12/11/2022

Step 1

Include the applied force P (acting horizontally, as in the usual setup), the reaction (normal) forces at A, B and at C, and the friction forces at B and C. Assume the weight of the cylinder is neglected, and take the friction at B and C to act so as to oppose any Show more…

Show all steps

Thanks for your feedback!

The rod is not to slip downward, however large the force P may be, i.e., the arrangement is said to be self-locking. Neglecting the weight of the cylinder, the minimum coefficients of static friction at A may have any value, but at B and Cthey have to be not less than tan(θ/2).