00:01
In this problem, we have been given that there is a roller coaster car which is having mass m and this is released from point a.
00:09
So its initial velocity at this point a is zero meter per second.
00:13
And we have to determine the distance edge, which will be required so that this roller coaster does not leave the contact at this point b.
00:23
So here this is a circular loop we can see of radius 7 .5 meters and we use simple energy conservation.
00:30
To find out the speed at this point c, which is also asked.
00:35
But before that, we observed that at this point b, as it does not leave the contact, in that case, the weight will provide the necessary centripetal force.
00:47
That's m v.
00:48
V square over r.
00:50
And this implies that the speed at point b, represented as vb, that will be root of gr, that will be root of 9 .8 times 7 .5.
01:01
And this comes out to be approximately 8 .6 meter per second...