The rotational constant of 127I 35Cl is 0.1142 cm-1. Calculate the ICl bond length. Given: m(35Cl) = 34.9688 mu and m(127I) = 126.9045 mu.
Added by David C.
Step 1
We know that 1 mu = 1.66053906660 x 10^-27 kg. So, m(35Cl) = 34.9688 mu = 34.9688 * 1.66053906660 x 10^-27 kg = 5.805 x 10^-26 kg And, m(127I) = 126.9045 mu = 126.9045 * 1.66053906660 x 10^-27 kg = 2.107 x 10^-25 kg Show more…
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