The rusting of iron is represented by the equation below. If you have 1.50 mol of oxygen, how many moles of Fe2O3 will there be after the iron has rusted completely? 4Fe + 3O2 --> 2Fe2O3 1.00 mol 3.00 mol 2.25 mol 2.00 mol 0.486 mol
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The balanced equation is: 4Fe + 3O2 -> 2Fe2O3 Now, we are given that we have 1.50 mol of oxygen (O2). We need to find out how many moles of Fe2O3 will be formed after the iron has rusted completely. From the balanced equation, we can see that 3 moles of O2 Show more…
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