The sample size is 8 and the level of confidence is 99%.
Added by Thomas H.
Step 1
Since the confidence level is 99%, we need to find the z-score that corresponds to the 0.5% in each tail of the normal distribution (100% - 99% = 1% divided by 2 = 0.5%). The z-score for 99% confidence level is approximately 2.576. Show more…
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