The sample space for an experiment contains five sample points. These sample points constitute mutually exclusive events. The probabilities of the sample points are: P(1) = P(2) = 0.1 P(3) = P(4) = 0.2 P(5) = 0.4 Find the probability of each of the following events: A : { Either 5 or 3 occurs } B : { Either 4 or 2 occurs } C : { 1 does not occur } P(A) = P(B) = P(C) =
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Given: - P(5) = 0.4 - P(3) = P(4) = 0.2 Therefore, P(A) = P(5) + P(3) = 0.4 + 0.2 = 0.6 Show more…
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The sample space for an experiment contains five sample points with probabilities as shown in the table to the right. Find the probability of each of the following events. A: {Either 1, 3, or 5 occurs} B: {Either 1, 2, or 4 occurs} C: {5 does not occur} Sample Points Probabilities P(A) = (Type an exact answer in simplified form.)
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If there are exactly 5 mutually exclusive, equally likely and independent events in a sample space then the probability of one of the events happening in a trial is (a) $\frac{1}{2}$ (b) $\frac{4}{5}$ (c) $\frac{1}{5}$ (d) $\frac{2}{5}$
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