Question

The series circuit in the figure contains an ideal battery with a constant terminal voltage V_B=60 V, an ideal inductor L=50 H, a R=11-ohm resistor, and a switch S. Initially, the switch is open, and there is no current in the inductor. At time t=0 s, the switch is suddenly closed. What is the current in the circuit 4.09 s after closing the switch?

Name: The series circuit in the figure contains an ideal battery with a constant terminal voltage VB=60 V, an ideal inductor L=50 H, a R=11-ohm resistor, and a switch S. Initially, the switch is open, and there is no current in the inductor. At time t=0 s, the switch is suddenly closed. What is the current in the circuit 4.09 s after closing the switch?
Uploaded: 2023-05-17T18:11:41-08:00
Duration: 1 min 23 s
Channel: Prabhu Ramji
Description: The series circuit in the figure contains an ideal battery with a constant terminal voltage VB=60 V, an ideal inductor L=50 H, a R=11-ohm resistor, and a switch S. Initially, the switch is open, and there is no current in the inductor. At time t=0 s, the switch is suddenly closed. What is the current in the circuit 4.09 s after closing the switch?

          The series circuit in the figure contains an ideal battery with a constant terminal voltage V_B=60 V, an ideal inductor L=50 H, a R=11-ohm resistor, and a switch S. Initially, the switch is open, and there is no current in the inductor. At time t=0 s, the switch is suddenly closed. What is the current in the circuit 4.09 s after closing the switch?

The series circuit in the figure contains an ideal battery with a constant terminal voltage VB=60 V, an ideal inductor L=50 H, a R=11-ohm resistor, and a switch S. Initially, the switch is open, and there is no current in the inductor. At time t=0 s, the switch is suddenly closed. What is the current in the circuit 4.09 s after closing the switch?

Added by Burçak M.

Fundamentals of Physics

David Halliday, Robert Resnick , Jearl… 10th Edition

Chapter 30

Instant Answer

Solved by Expert Prabhu Ramji

05/17/2023

Step 1

First, we need to find the time constant of the RL circuit. The time constant τ (tau) is given by the formula: τ = L / R where L is the inductance (50 H) and R is the resistance (11 ohms). τ = 50 H / 11 ohms ≈ 4.55 s Show more…

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The series circuit in the figure contains an ideal battery with a constant terminal voltage V_B=60 V, an ideal inductor L=50 H, a R=11-ohm resistor, and a switch S. Initially, the switch is open, and there is no current in the inductor. At time t=0 s, the switch is suddenly closed. What is the current in the circuit 4.09 s after closing the switch?