The service-time distribution describes the probability P that the service time of the customer will be no more than t hours. If m is the mean number of customers serviced in an hour, then p = 1 - e^-mt. Suppose a computer technical support representative can answer calls from 6 customers in an hour. What is the probability that a customer will be on hold less than 30 minutes? a. 65% b. 75% c. 85% d. 95%
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We are given that the representative can answer calls from 6 customers in an hour. So, m = 6. Show more…
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