Question

The Sharp-razor Company manufactures two types of electric shavers. One shaver is cordless and It requires 5 hours to manufacture. The other shaver has an electric cord and it takes 3 hours to manufacture it. The company has only 16 work hours per day to manufacture shavers. The despatch department can pack and ship at most 300 shavers per day. Let $z$ be the number of cordless shavers made per day and $y$ be the number of shavers with a cord manufactured per day. The correct system of linear inequalities that represents this situation is a. $5x + 3y \le 16$; $x + y \le 3$ b. $5x + 3y \le 300$; $x + y \le 3$ c. $5x + 3y \le 16$; $x + y \ge 3$ d. $5x + 3y \ge 16$; $x + y \ge 3$

          The Sharp-razor Company
manufactures two types of electric
shavers. One shaver is cordless and
It requires 5 hours to manufacture.
The other shaver has an electric
cord and it takes 3 hours to
manufacture it. The company has
only 16 work hours per day to
manufacture shavers. The despatch
department can pack and ship at
most 300 shavers per day. Let $z$ be
the number of cordless shavers
made per day and $y$ be the
number of shavers with a cord
manufactured per day. The correct
system of linear inequalities that
represents this situation is
a. $5x + 3y \le 16$; $x + y \le 3$
b. $5x + 3y \le 300$; $x + y \le 3$
c. $5x + 3y \le 16$; $x + y \ge 3$
d. $5x + 3y \ge 16$; $x + y \ge 3$
        
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The Sharp-razor Company
manufactures two types of electric
shavers. One shaver is cordless and
It requires 5 hours to manufacture.
The other shaver has an electric
cord and it takes 3 hours to
manufacture it. The company has
only 16 work hours per day to
manufacture shavers. The despatch
department can pack and ship at
most 300 shavers per day. Let z be
the number of cordless shavers
made per day and y be the
number of shavers with a cord
manufactured per day. The correct
system of linear inequalities that
represents this situation is
a. 5x + 3y ≤ 16; x + y ≤ 3
b. 5x + 3y ≤ 300; x + y ≤ 3
c. 5x + 3y ≤ 16; x + y ≥ 3
d. 5x + 3y ≥ 16; x + y ≥ 3

Added by Belen H.

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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The Sharp-fazor Company manufactures two types of electric shavers. One shaver is cordless and it requires 5 hours to manufacture. The other shaver has an electric cord and it takes 3 hours to manufacture it. The company has only 16 work hours per day to manufacture shavers. The dispatch department can pack and ship at most 300 shavers per day. Let x be the number of cordless shavers made per day and y be the number of shavers with a cord manufactured per day. The correct system of linear inequalities that represents this situation is: a. 5x + 3y <= 16; x + y <= 3
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Transcript

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00:01 Here the random variable x represents the number of cord type trimmer manufacturer and the variable y represents the number of cordless type trimmer manufacturer.
00:15 Then total hours needed.
00:19 Total hours need to manufacture x cord trimmer equal to 2x and total hours needed to manufacturer to manufacturer while cordless trimmer.
00:33 3y and the total horse of labour is equal to so total labour equal to 2x plus 4y less than or equal to 800 and another equation we may get it as x plus 2y less than or equal to 400 mark it as equation 1 and it is number of trimmers less than or equal to 300 so which implies x plus y less than or equal to 300 market as equation 2 and another point you is y less than or equal to 100 and x less than or equal to 200 so for this constraints we will have a graphical representation like this okay so it is zero then x -axis y -axis 100 200 300 and here also 100 200 300 300 400, etc.
01:31 So now plot these values...
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