Question

The shear stress-strain diagram for a steel alloy is shown above where τγ =350 MPa. The bolt with a 5 mm diameter is made of this material and used in the lap joint. Given that: v = 0.3, determine the force P (kN) required to cause the material to yield. Hint: Find yielding shear from figure.

Name: the shear stress strain diagram for a steel alloy is shown above where 350 mpa the bolt with a 5 mm diameter is made of this material and used in the lap joint given that v 03 determine the 74523
Uploaded: 2022-01-25T12:04:10-08:00
Duration: 2 min 15 s
Channel: Mahendra Kumar
Description: the shear stress strain diagram for a steel alloy is shown above where 350 mpa the bolt with a 5 mm diameter is made of this material and used in the lap joint given that v 03 determine the 74523

          The shear stress-strain diagram for a steel alloy is shown above
where τγ =350 MPa. The bolt with a 5 mm diameter is made of this
material and used in the lap joint. Given that: v = 0.3, determine
the force P (kN) required to cause the material to yield. Hint:
Find yielding shear from figure.

Added by Denise K.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Mahendra Kumar

01/25/2022

Step 1

Given diameter of the bolt, d = 5 mm Shear area, A = π*(d/2)^2 A = π*(5/2)^2 A = π*(2.5)^2 A = π*6.25 A = 19.635 mm^2 Show more…

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The shear stress-strain diagram for a steel alloy is shown above where τγ =350 MPa. The bolt with a 5 mm diameter is made of this material and used in the lap joint. Given that: v = 0.3, determine the force P (kN) required to cause the material to yield. Hint: Find yielding shear from figure.