Question

The single line diagram, shown below, has the following ratings and reactances: G1: 100 MVA, 25 kV, X1 = X2 = 0.20, X0 = 0.05 per unit, Zng = j0.03 G2: 100 MVA, 13.8 kV, X1 = X2 = 0.20, X0 = 0.05 per unit, Zng = j0.03 T1: 100 MVA, 25 kV (Y) / (230) kVY, X = 0.05 per unit T2: 100 MVA, 13.8 kV (Δ) / (230) kVY, X = 0.05 per unit Line 1-2: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3 Line 1-3: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3 Line 2-3: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3 Using a 100 MVA, 230 kV base for the transmission lines, draw the per-unit sequence networks and reduce them to their Thevenin equivalents, "looking in" at bus 3. Neglect transformer phase shifts. Compute the fault currents for a bolted three-phase fault at bus 3. |V| = 1.0 pre-fault. Zbus matrices appear below. Zbus 0 = j * [[0.1080, 0.0216, 0.0648, 0.0795, 0.0000, 0.0443, 0.0330, 0.0159, 0.0000, 0.0330, 0.1989, 0.0477, 0.0000, 0.0795, 0.0159, 0.0477, 0.0955, 0.0000, 0.0000, 0.0000, 0.0000, 0.1400]] 0.0000 0.0795 0.0648 0.0000 0.0795 0.0648 0.0216 Zbus 1 = Zbus 2 = j * [[0.1397, 0.1103, 0.1250, 0.1118, 0.0882, 0.1397, 0.1250, 0.0882, 0.1118, 0.1250, 0.1750, 0.1000, 0.1000, 0.0882, 0.1000, 0.1294, 0.0706, 0.1118, 0.1000, 0.0706, 0.1294]] 0.0882 0.1118 0.1250 0.1103 1. The single line diagram, shown below, has the following ratings and reactances: G1: 100 MVA, 25 kV, X1 = X2 = 0.20, X0 = 0.05 per unit, Zng = j0.03 G2: 100 MVA, 13.8 kV, X1 = X2 = 0.20, X0 = 0.05 per unit, Zng = j0.03 T1: 100 MVA, 25 kV (Y) / 230 kVY, X = 0.05 per unit T2: 100 MVA, 13.8 kV (Δ) / 230 kVY, X = 0.05 per unit Line 1-2: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3 Line 1-3: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3 Line 2-3: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3 Using a 100 MVA, 230 kV base for the transmission lines, draw the per-unit sequence networks and reduce them to their Thevenin equivalents, "looking in" at bus 3. Neglect transformer phase shifts. Compute the fault currents for a bolted three-phase fault at bus 3. |V| = 1.0 pre-fault. Zbus matrices appear below. Zbus 0 = j * [[0.1080, 0.0216, 0.0648, 0.0795, 0.0000, 0.0443, 0.0330, 0.0159, 0.0000, 0.0330, 0.1989, 0.0477, 0.0000, 0.0795, 0.0159, 0.0477, 0.0955, 0.0000, 0.0000, 0.0000, 0.0000, 0.1400]] 0.0000 0.0795 0.0648 0.0000 0.0795 0.0648 0.0216 Zbus 1 = Zbus 2 = j * [[0.1397, 0.1103, 0.1250, 0.1118, 0.0882, 0.1397, 0.1250, 0.0882, 0.1118, 0.1250, 0.1750, 0.1000, 0.1000, 0.0882, 0.1000, 0.1294, 0.0706, 0.1118, 0.1000, 0.0706, 0.1294]] 0.0882 0.1118 0.1250 0.1103

          The single line diagram, shown below, has the following ratings and reactances:

G1: 100 MVA, 25 kV, X1 = X2 = 0.20, X0 = 0.05 per unit, Zng = j0.03
G2: 100 MVA, 13.8 kV, X1 = X2 = 0.20, X0 = 0.05 per unit, Zng = j0.03
T1: 100 MVA, 25 kV (Y) / (230) kVY, X = 0.05 per unit
T2: 100 MVA, 13.8 kV (Δ) / (230) kVY, X = 0.05 per unit
Line 1-2: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3
Line 1-3: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3
Line 2-3: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3

Using a 100 MVA, 230 kV base for the transmission lines, draw the per-unit sequence networks and reduce them to their Thevenin equivalents, "looking in" at bus 3. Neglect transformer phase shifts. Compute the fault currents for a bolted three-phase fault at bus 3. |V| = 1.0 pre-fault. Zbus matrices appear below.

Zbus 0 = j * [[0.1080, 0.0216, 0.0648, 0.0795, 0.0000, 0.0443, 0.0330, 0.0159, 0.0000, 0.0330, 0.1989, 0.0477, 0.0000, 0.0795, 0.0159, 0.0477, 0.0955, 0.0000, 0.0000, 0.0000, 0.0000, 0.1400]]
0.0000
0.0795
0.0648
0.0000
0.0795
0.0648
0.0216

Zbus 1 = Zbus 2 = j * [[0.1397, 0.1103, 0.1250, 0.1118, 0.0882, 0.1397, 0.1250, 0.0882, 0.1118, 0.1250, 0.1750, 0.1000, 0.1000, 0.0882, 0.1000, 0.1294, 0.0706, 0.1118, 0.1000, 0.0706, 0.1294]]
0.0882
0.1118
0.1250
0.1103

1. The single line diagram, shown below, has the following ratings and reactances:
G1: 100 MVA, 25 kV, X1 = X2 = 0.20, X0 = 0.05 per unit, Zng = j0.03
G2: 100 MVA, 13.8 kV, X1 = X2 = 0.20, X0 = 0.05 per unit, Zng = j0.03
T1: 100 MVA, 25 kV (Y) / 230 kVY, X = 0.05 per unit
T2: 100 MVA, 13.8 kV (Δ) / 230 kVY, X = 0.05 per unit
Line 1-2: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3
Line 1-3: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3
Line 2-3: 100 MVA, 230 kV, X1 = X2 = 0.1, X0 = 0.3

Using a 100 MVA, 230 kV base for the transmission lines, draw the per-unit sequence networks and reduce them to their Thevenin equivalents, "looking in" at bus 3. Neglect transformer phase shifts. Compute the fault currents for a bolted three-phase fault at bus 3. |V| = 1.0 pre-fault. Zbus matrices appear below.

Zbus 0 = j * [[0.1080, 0.0216, 0.0648, 0.0795, 0.0000, 0.0443, 0.0330, 0.0159, 0.0000, 0.0330, 0.1989, 0.0477, 0.0000, 0.0795, 0.0159, 0.0477, 0.0955, 0.0000, 0.0000, 0.0000, 0.0000, 0.1400]]
0.0000
0.0795
0.0648
0.0000
0.0795
0.0648
0.0216

Zbus 1 = Zbus 2 = j * [[0.1397, 0.1103, 0.1250, 0.1118, 0.0882, 0.1397, 0.1250, 0.0882, 0.1118, 0.1250, 0.1750, 0.1000, 0.1000, 0.0882, 0.1000, 0.1294, 0.0706, 0.1118, 0.1000, 0.0706, 0.1294]]
0.0882
0.1118
0.1250
0.1103

the single line diagram shown below has the following ratings and reactances g1 100 mva 25 kv x1 x2 020 x0 005 per unit zng j003 g2 100 mva 138 kv x1 x2 020 x0 005 per unit zng j003 t1 100 m 15255

Added by Brett H.

Question

Please give Ace some feedback