The solar energy incident on the roof in 1 hour of dimension 8m×20m will be ?
Added by Mia M.
Step 1
Given that the power per unit area (intensity) is 1.6 x 10^3 W/m^2 and the total area of the roof is 8m x 20m = 160 m^2. Total power = Intensity x Total area Total power = 1.6 x 10^3 W/m^2 x 160 m^2 Total power = 1.6 x 10^3 x 160 Total power = 1.6 x 10^5 W Show more…
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