The solubility of Bi$_2$S$_3$ was found experimentally to be 1.0 x 10$^{-15}$ mol per liter. Calculate the value for K$_{sp}$. Bi$_2$S$_3$ ( ightleftharpoons) 2Bi$^{3+}$(aq) + 3S$^{2-}$(aq) 3.0 x 10$^{-12}$ 8.9 x 10$^{-44}$ 1.6 x 10$^{-8}$ 6.8 x 10$^{-23}$ 7.5 x 10$^{-18}$ 1.1 x 10$^{-73}$ 3.9 x 10$^{-5}$ 1.5 x 10$^{-6}
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Write the balanced chemical equation for the dissolution of Bi2S3: Bi2S3 (s) <=> 2Bi^3+ (aq) + 3S^2- (aq) Show more…
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