00:01
To determine the solubility product constant of magnesium phosphate, we need to write the equation first.
00:08
We have three moles of magnesium plus two moles of the phosphate ion.
00:16
And we're told that we had the solubility, we're given the solubility product, we're to determine its solubility in grams per 100 ml.
00:30
So the solubility, let's say if the solubility of magnesium phosphate is equal to s, it would mean that a concentration of magnesium, this is going to be 2 plus, would be 3s.
00:49
And that of the phosphate, and that of phosphate po4 3 minus would be 2s.
00:57
So the ksp then, the ksp is basically 3s 3s cubed multiplied by 2s squared.
01:16
Right, so what we have is 27 times s cubed multiplied by 4s squared.
01:22
So equals to the ksp.
01:25
So this is the expression for the ksp, which would mean that the ksp, which we're given as 1 times 10 to the power of minus 1 .04 times 10 to the power of minus 24, is equal to 27 times 4 is 80 plus 108, s raised to the power of 5.
01:50
Right, so when you look at that, you will have s will be the fifth root of 1 .04 times 10 to the power of minus 24 divided by 108...