Question

The solution of the non-exact differential equation $y \, dx + (3 + 3x - y)dy = 0$ is: $(1+x)-(y^4)/4=C$ $(y^3)-(y^4)/[4(1+x)] =C$ None of the above $(y^3) (1+x)-(y^4)/4=C$ The solution of the Bernoulli equation $y' + \frac{y}{x} - \sqrt{y} = 0$ is: y=((1/3) x+cx^(-1/(2))^(1/2) None of the above y=(x+cx^(1/2))^2 y=((1/3) x+cx^(-1/2))^2

          The solution of the non-exact differential equation $y \, dx + (3 + 3x - y)dy = 0$ is:

$(1+x)-(y^4)/4=C$
$(y^3)-(y^4)/[4(1+x)] =C$
None of the above
$(y^3) (1+x)-(y^4)/4=C$
The solution of the Bernoulli equation $y' + \frac{y}{x} - \sqrt{y} = 0$ is:

y=((1/3) x+cx^(-1/(2))^(1/2)
None of the above
y=(x+cx^(1/2))^2
y=((1/3) x+cx^(-1/2))^2

The solution of the non-exact differential equation y dx + (3 + 3x - y)dy = 0 is:

(1+x)-(y^4)/4=C
(y^3)-(y^4)/[4(1+x)] =C
None of the above
(y^3) (1+x)-(y^4)/4=C
The solution of the Bernoulli equation y' + (y)/(x) - √(y) = 0 is:

y=((1/3) x+cx^(-1/(2))^(1/2)
None of the above
y=(x+cx^(1/2))^2
y=((1/3) x+cx^(-1/2))^2

Added by Patrick C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sachin Rao

Step 1

To solve this, we can check if it is an exact differential equation by checking if the partial derivative of the coefficient of dx with respect to y is equal to the partial derivative of the coefficient of dy with respect to x. In this case, the partial Show more…

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The solution of the non-exact differential equation y dx + (3 + 3x - y)dy = 0 is: (1+x)-(y^4)/4-C (y^3)-(y^4)/[4(1+x)] = C None of the above (y^3) (1+x)-(y^4)/4-C The solution of the Bernoulli equation y' + 2 - vy = 0 is: y-((1/3) xtcx^(-1/2))^(1/2) None of the above y-(x+cx^(1/2))^2 y=((1/3) xtcx^(-1/2))^2