Question

The space between two square flat parallel plates is filled with oil. Each side of the plate is 60 cm. The thickness of the oil film is 12.5 mm. The upper plate, which moves at 2.5 m/s, requires a force of 98.1 N to maintain the speed. Determine a) the dynamic viscosity in poise, b) the kinematic viscosity of the oil in stokes if the specific gravity of the oil is 0.95.

Name: the space between two square flat parallel plates is filled with oil each side of the plate is 60cm the thickness of the oil film is 125mm the upper plate which moves at 25 ms requires a for 02864
Uploaded: 2022-05-06T15:56:49-08:00
Duration: 1 min 41 s
Channel: Shaiju T
Description: the space between two square flat parallel plates is filled with oil each side of the plate is 60cm the thickness of the oil film is 125mm the upper plate which moves at 25 ms requires a for 02864

          The space between two square flat parallel plates is filled with oil. Each side of the plate is 60 cm. The thickness of the oil film is 12.5 mm. The upper plate, which moves at 2.5 m/s, requires a force of 98.1 N to maintain the speed. Determine a) the dynamic viscosity in poise, b) the kinematic viscosity of the oil in stokes if the specific gravity of the oil is 0.95.

Added by Samuel M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shaiju T

05/06/2022

Step 1

1 N - Thickness of oil film (\( \delta y \)) = 12.5 mm = 0.0125 m - Area of plate (A) = side length squared = \( 0.6 \, m \times 0.6 \, m = 0.36 \, m^2 \) - Velocity (v) = 2.5 m/s Plugging in the values: \[ \eta = \frac{98.1 \, N \times 0.0125 \, m}{8 \times 0.36 Show more…

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The space between two square flat parallel plates is filled with oil. Each side of the plate is 60 cm. The thickness of the oil film is 12.5 mm. The upper plate, which moves at 2.5 m/s, requires a force of 98.1 N to maintain the speed. Determine a) the dynamic viscosity in poise, b) the kinematic viscosity of the oil in stokes if the specific gravity of the oil is 0.95.