The space factor when determining the efficiency of algorithm is measured by Counting the minimum memory needed by the algorithm Counting the maximum memory needed by the algorithm Counting the average memory needed by the algorithm Counting the maximum disk space needed by the algorithm
Added by Shannon R.
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The space factor refers to the amount of memory resources an algorithm requires to complete its execution. Show more…
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Key Concepts
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The complexity of a computer algorithm is the number of operations or steps the algorithm needs to complete its task assuming there are $n$ pieces of input (for example, the number of steps needed to put $n$ numbers in ascending order). Four algorithms for doing the same task have complexities of $\mathrm{A}: n^{3 / 2}, \mathrm{B}: n \log _{2} n, \mathrm{C}: n\left(\log _{2} n\right)^{2},$ and $\mathrm{D}: \sqrt{n} \log _{2} n .$ Rank the algorithms in order of increasing efficiency for large values of $n$ Graph the complexities as they vary with $n$ and comment on your observations.
Applications of the Derivative
L'Hôpital's Rule
Consider the following algorithms (all of which perform the same task) and their associated statement counts: 1. Algorithm 1, Fn = 500n - 2 2. Algorithm 2, Gn = 30n ln n + 5 3. Algorithm 3, Hn = 2^n + 7 4. Algorithm 4, Kn = 250∙∙∙∙∙n + 11 Here, n denotes the size of the input. Which of the following statements is/are true? Algorithm 1 is more efficient than Algorithm 2 for large input sizes Algorithm 2 is more efficient than Algorithm 1 for small input sizes Algorithm 2 is more efficient than Algorithm 3 for large input sizes Algorithm 3 is more efficient than Algorithm 2 for large input sizes Algorithm 4 is more efficient than Algorithm 2 for large input sizes Algorithm 1 is more efficient than Algorithm 4 for small input sizes.
Sri K.
'A divide and conquer algorithm X works in the following way: Given a problem instance of input size n. If n is less than then the algorithm solves the problem instance directly with a constant number of steps: If n is at least 4, algorithm X divides the given problem instance into exactly two smaller problem instances and solve them recursively: Furthermore, whenever algorithm X divides given problem instance of size n into smaller instances with sizes a and b, then a + b n and %n < a,b < n.'
Shyam P.
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