00:02
Here in this problem, we have to find the amount of heat required to raise the temperature of 1 .55 kilogram of copper block from 33 degrees celsius to 95 degrees celsius.
00:16
And specific heat capacity of copper is 0 .385 joule per gram per kelvin.
00:22
Now, recall the formula, q is equal to m, c, delta, t.
00:32
Q is the heat required.
00:33
M is the mass of the substance.
00:36
C is the specific heat capacity of the substance and delta t is the difference in temperature.
00:43
Here, mass given, mass of the copper given 1 .55 kilogram.
00:50
So let's convert it into gram.
00:52
1 .55 kilogram.
00:55
So we'll convert it into gram times 10 to the power 3 gram.
01:00
Since one kilogram is 10 to the power 3 gram.
01:05
And that is the mass of the copper block.
01:11
Now we'll find out delta t, the difference in temperature.
01:16
Delta t is final temperature is 95 degrees celsius and initial is 33 degrees celsius.
01:24
So 95 minus 33 degrees celsius...