00:01
So the question is from the specific heat and the process involved in the given problem are first one that ag solid that are given 25 degrees celsius 298 kelvin that give the formation of ag solid and at a 962 degrees celsius and 1 2 3 3 5 kelvin.
00:37
Then another one is ag solid, ag solid react with 9 6 2 degrees celsius ok, at 1, 2, 3, 5 kelvin to give the formation of ag liquid and 9, 6, 2 degrees celsius, 1, 2, 3, 5 kelvin.
01:05
So this is the reaction.
01:08
So for process first, for first process, it would be the calculate amount of heat absorbed, we choose the equation q1 equal m into c is for the pnl into delta t, that is t2 minus t1.
01:34
Then put all these value where q1 is amount of heat absorbed, okay? and m is mass of silver, that is given m equal 9 .70 gram.
01:46
And t2 we have given 1, 2, 3, 5 kelvin, and t1 we have 298 kelvin.
01:56
And we also know that cp equal 0 .235.
02:02
Just putting all this value into the equation.
02:05
Let me get the answer.
02:06
So 9 .70 gram multiplied by 0 .235 joule per gram kelvin multiplied by 1 .235 minus 298.
02:24
Okay? and then we get the answer q1...