00:01
All right, in this question, the speed limit of a certain roadway is 90 km per hour.
00:04
And suppose that speeding fines are made proportional to the amount by which the vehicle's momentum exceeds the momentum it would have when the traveling when traveling at the speed limit.
00:13
So if the driving fine for 190 kilometer per hour, there is 100 kilometers above kilometer per hour above the speed limit is 80.
00:21
So what is the fine for 1090 and this match speed? so we know that the fine is proportional to the exceeding momentum.
00:30
Let's say the change in the momentum.
00:32
So in this case, the fine, let's say represented by f is equal to k times delta p.
00:38
And delta p is nothing but m times delta v, right? because the mass is going to remain the same.
00:44
Now in case one, if the delta v is 100, the fine is 80.
00:49
So it means that 80 is equal to k times 100.
00:51
This means that the value of 80 over 100, dividing both sides by 100, is actually equal to k.
00:58
So the value of k is 0 .8.
01:00
Since we got the value of k, the equation of fine and change in the momentum will be f is equal to the fine f is equal to 0 .8 times...