00:01
So in this problem, we're told that the spring concert at a certain high school charged different amounts for student and adult tickets.
00:06
They charge $6 for students and $8 for adults.
00:09
So on the night of the concert, they sold a total of 176 tickets, and the total amount of money that they brought in was $1 ,254.
00:17
We want to find, well, how many students and how many adults want.
00:21
To do this, we're going to set up a system of equations.
00:24
Well, we don't know the number of students and the number of adults, so i'm going to let s equal the number of students, who is, attended, and we're going to let a represent the number of adults.
00:35
So the first piece of information that we're told is 176 total tickets were sold, meaning when we add the number of students, which is s, to the number of adults that go, which is a, it should equal to 176.
00:49
So that's our first equation.
00:51
The second piece of information deals with the total amount of money.
00:54
Well, students are $6 each.
00:57
So to find the total cost that all the student tickets bring in, we would multiply the number of students, which is s, by the cost per ticket, which is six.
01:05
So 6s represents the total value that was brought in for the students.
01:10
Well, then we would add this to the total amount brought in by the adults.
01:14
Well, it's $8 for an adult ticket, and we have a representing the total number of when.
01:19
So a will represent the total number of adults, or the value that the adults bring in.
01:25
So when we bring in or add up the amount the students bring in plus the amount the adults bring in, it should equal to the total cost, 1 ,254.
01:34
And now we have our system.
01:36
So now we can go ahead and solve either by substitution or elimination.
01:41
I'm going to use elimination in this case...