Question

The spring of the pressure gauge shown in Figure P14.7 has a force constant of $1250 \mathrm{N} / \mathrm{m},$ and the piston has a diameter of $1.20 \mathrm{cm} .$ As the gauge is lowered into water in a lake, what change in depth causes the piston to move in by $0.750 \mathrm{cm} ?$ (FIGURE CANT COPY)

          The spring of the pressure gauge shown in Figure P14.7 has a force constant of $1250 \mathrm{N} / \mathrm{m},$ and the piston has a diameter of $1.20 \mathrm{cm} .$ As the gauge is lowered into water in
a lake, what change in depth causes the piston to move in by $0.750 \mathrm{cm} ?$
(FIGURE CANT COPY)

Added by Kelly M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

05/22/2022

Step 1

20 cm. Area = π * (diameter/2)^2 Area = π * (0.012 m / 2)^2 Area = π * (0.006 m)^2 Area = π * 0.000036 m^2 Area = 0.000113 m^2 Show more…

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The spring of the pressure gauge shown in Figure P14.7 has a force constant of $1250 mathrm{N} / mathrm{m},$ and the piston has a diameter of $1.20 mathrm{cm} .$ As the gauge is lowered into water in a lake, what change in depth causes the piston to move in by $0.750 mathrm{cm} ?$