Question

The standard enthalpy of formation of propene, C3H6 is + 20.6 kJ mol ^-1 . The heats of formation of CO2 (g) and H2O (l) are - 394 kJ mol ^-1 . and - 285.8 kJ mol ^-1 .Calculate the heat of combustion of one mole of C3H6 . A. 1721.2 kJ mol ^-1 . B. - 1978.1 kJ mol ^-1 . C. 2060.0 kJ mol ^-1 . D. 2221.6 kJ mol ^-1 .

Name: the standard enthalpy of formation of propene c3h6 is 206 kj mol 1 the heats of formation of co2 g and h2o l are 394 kj mol 1 and 2858 kj mol 1 calculate the heat of combustion of one mole o 04466
Uploaded: 2024-11-27T14:48:14-08:00
Duration: 2 min 43 s
Channel: Prabhakar Kumar
Description: the standard enthalpy of formation of propene c3h6 is 206 kj mol 1 the heats of formation of co2 g and h2o l are 394 kj mol 1 and 2858 kj mol 1 calculate the heat of combustion of one mole o 04466

          The standard enthalpy of formation of propene, C3H6 is + 20.6 kJ mol ^-1 . The heats of formation of CO2 (g)  and H2O (l)  are - 394 kJ mol ^-1 . and - 285.8 kJ mol ^-1 .Calculate the heat of combustion of one mole of C3H6 .
A. 1721.2 kJ mol ^-1 .
B. - 1978.1 kJ mol ^-1 .
C. 2060.0 kJ mol ^-1 .
D. 2221.6 kJ mol ^-1 .

Added by Chad Z.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Prabhakar Kumar

11/27/2024

Step 1

5O2 -> 3CO2 + 3H2O From this equation, we can see that one mole of propene (C3H6) reacts to form three moles of carbon dioxide (CO2) and three moles of water (H2O). The heat of combustion is the change in enthalpy (ΔH) for this reaction. According to Hess's law, Show more…

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The standard enthalpy of formation of propene, C3H6 is + 20.6 kJ mol ^-1 . The heats of formation of CO2 (g) and H2O (l) are - 394 kJ mol ^-1 . and - 285.8 kJ mol ^-1 .Calculate the heat of combustion of one mole of C3H6 . A. 1721.2 kJ mol ^-1 . B. - 1978.1 kJ mol ^-1 . C. 2060.0 kJ mol ^-1 . D. 2221.6 kJ mol ^-1 .