The standard enthalpy of the above reaction is -3353 kJ. How much heat is released by the complete oxidation of 27 g of aluminum at 25 degrees Celsius and 1 atm? Also, calculate the work involved in the reaction. 2Al(s) + 3/2O2(g) -> Al2O3(s)
Added by Ryan C.
Step 1
The molar mass of aluminum is approximately 27 g/mol, so there is 1 mol of aluminum in 27 g. The given reaction shows that 2 moles of aluminum react to release -3353 kJ of heat. Therefore, 1 mol of aluminum will release half of this amount, or -1676.5 kJ. So, Show more…
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