00:01
By the relay criteria we can write the angular separation between two objects, that is theta, should be greater than 1 .22, multiplied with lambda divided by t, where lambda is the wavelength.
00:30
So from this we will get, t should be greater than 1 .22 lambda divided by theta.
00:39
So the minimum value of the diameter, so d minimum, d minimum will be equals to 1 .22 lambda divided by theta.
00:51
Let this equation be equation number one.
00:55
Now we have been given that the length is equal to 8 .6 light years.
01:06
So we will convert the light year into meter.
01:10
So we will write 8 .6 multiplied with 3 multiplied with 10 to the power of 8 multiplied with 365 days multiplied with 24 hours multiplied with 3600 seconds.
01:27
So after solving we will get the length equals to 8 .14 multiplied with 10 to the power of 16 meter.
01:37
This is the length 16 meters.
01:40
Now let's write the wavelength given.
01:43
So wavelength is given as 550 nanometer.
01:47
So it is equals to 550 multiplied with 10 to the power of minus 9 meters.
01:54
Now let us calculate the angular separation of stars...