00:01
Hello students, in this question, we are going to consider, let x be a random variable that starting salaries of the individual within an mba degree.
00:19
So, mu is nothing but mean, that is 60 ,000.
00:24
Then standard deviation is equals to 7500.
00:30
So that, i can able to write z is equals to x minus mu divided by sigma.
00:36
So, x minus 60 ,000, the whole divided by 7500 follows the standard normal.
00:46
So, in question number 8 is given, probability of x is greater than 50 ,000, that is probability of x minus mu divided by sigma is greater than 50 ,000 minus 60 ,000, the whole divided by 7500.
01:10
So, by simplifying it, we'd be getting probability of z, that is probability of z, which is greater than minus 1 .333.
01:22
So, that is 1 minus probability of z is less than minus 1 .33.
01:30
So, we need to simplify, that is 1 minus 0 .091217.
01:39
So, that is 0 .908783.
01:44
Now, let's move on to question number b.
01:47
Here, we need to find the x naught.
01:50
So, we need to find x naught, that is probability of x less than x naught is equals to 0 .25, that is probability of x minus mu divided by sigma less than x naught minus 60 ,000, the whole divided by 7500.
02:12
So, this is equals to 0 .25, that is probability of z is less than x naught minus 60 ,000, the whole divided by 7500...