Question

The steady-state concentration of cells and glucose in the fermenter were measured and recorded in a 500 mL chemostat. Calculate the growth rate if the medium flow rate was varied with a constant inlet concentration of glucose of 100 g/L. Flowrate F, 30 50 70 90 200 mL/h Cell Conc. X 6.00 5.95 5.91 5.80 0 (g/L) Glucose 0.5 1.0 2.0 4.0 100 Conc, S (g/L)

          The steady-state concentration of cells and glucose in the fermenter were measured and
recorded in a 500 mL chemostat. Calculate the growth rate if the medium flow rate was
varied with a constant inlet concentration of glucose of 100 g/L.
Flowrate F,
30
50
70
90
200
mL/h
Cell Conc. X
6.00
5.95
5.91
5.80
0
(g/L)
Glucose
0.5
1.0
2.0
4.0
100
Conc, S (g/L)
        
Show more…
The steady-state concentration of cells and glucose in the fermenter were measured and
recorded in a 500 mL chemostat. Calculate the growth rate if the medium flow rate was
varied with a constant inlet concentration of glucose of 100 g/L.
Flowrate F,
30
50
70
90
200
mL/h
Cell Conc. X
6.00
5.95
5.91
5.80
0
(g/L)
Glucose
0.5
1.0
2.0
4.0
100
Conc, S (g/L)

Added by Christopher B.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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The steady-state concentration of cells and glucose in the fermenter was measured and recorded in a 500 mL chemostat. Calculate the growth rate if the medium flow rate was varied with a constant inlet concentration of glucose of 100 g/L. Flow rate F: 30 mL/h Cell Conc. X: 6.00 g/L Glucose Conc. S: 0.5 g/L 50 70 90 200 5.95 5.91 5.80 0 2.0 4.0 100
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Transcript

-
0:00 Hello everyone.
00:01 So, as we know here that dna have the four bases.
00:07 Okay, this has four nitrogenous bases between purins and pynevidins.
00:14 So they are adenine that is represented as a.
00:20 Then there is thymine which is represented as t.
00:25 Then there is cytosin represented as c.
00:31 And there is guanin which is represented as g.
00:35 So we know that in particularly dna, we find that adenine is having double bonds with the thymine and cytosin is having triple bonds with guanine.
00:50 And these are hydrogen bonds.
00:53 These are actually the hydrogen bonds.
00:57 Often we find that there are hydrogen bonds.
00:59 So now if we want to extract this dna, extract, then we'll find that we need to break the hydrogen bonds, break bonds between the pairs.
01:19 And now to break this bond, we always need a enzyme.
01:25 And that enzyme is known as the dna helicase.
01:29 Dna helicase.
01:33 Dna helicase disrupt this hydrogen bonds between the basic pair to separate them into a y shape.
01:42 Now, as this dna helicase work, the dna is actually broken.
01:49 Broken into a y shape type of structure and that is known as the duplicate fork.
01:59 That is known as duplicate fork.
02:05 And like the place will be the first replica template.
02:14 So this place, this place will be first replica template.
02:25 Now if we say here that what are the formations or what are the processes or steps.
02:34 So, the step one is basically replication, replication forc formation...
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